Question 519000: If ALICE is twice as old as BRENDA and BRENDA is half as old as CATHERINE, How old is each of them when their total ages are 50 ? Found 2 solutions by Maths68, richwmiller:Answer by Maths68(1474) (Show Source):
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Present age of Catherine = x
Present age of Brenda = x/2
Present age of Alice = 2*(x/2) = x
x+x/2+x=50
2x+x/2=50*2
Multiply by 2 both sides of the equation
4x+x=100
5x=100
5x/5=20
x=20
Present age of Catherine = x = 20 years old
Present age of Brenda = x/2 = 20/2 = 10 years old
Present age of Alice = 2*(x/2) = x = 20 years old