SOLUTION: Please answer this..ASAP.Thanks..a man is four years older than his wife and 5 times as old as his son.when the so was born,the age of the wife is six-seventh that of her husband's

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Please answer this..ASAP.Thanks..a man is four years older than his wife and 5 times as old as his son.when the so was born,the age of the wife is six-seventh that of her husband's      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 517559: Please answer this..ASAP.Thanks..a man is four years older than his wife and 5 times as old as his son.when the so was born,the age of the wife is six-seventh that of her husband's age. Find the age of the wife..
Found 2 solutions by Maths68, MathTherapy:
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!
Let
Present age of Man = m
Present age of Wife = w
Present age of Son = s
===============================================================================
Man is 4 years older than his wife
m=w+4
m-w-4=0...........(1)
================================================================================
5 times as old as his son.
m=5s
m-5s=0............(2)
================================================================================
Age of the man when son was born means that we have to subtract age of Son from the age of Man and age of wife so the age of the man was (m-s) and age of wife (w-s) then the age of the wife is six-seventh that of her husband's age.
w-s=6/7(m-s)
7(w-s)=6(m-s)
7w-7s=6m-6s
7w-7s-6m+6s=0
7w-s-6m=0...........(3)
================================================================================
We have three equations and three unkowns (m,w,s)
m-w-4=0...........(1)
m-5s=0............(2)
7w-s-6m=0...........(3)
Subtract (2) from (1)
m-w-4=0
-m+5s=0
------------
5s-w-4=0................(4)
Multiply (2) by 6 and add to (3)
6m-30s=0
7w-s-6m=0
---------------
7w-31s=0............(5)
Multiply (4) by 7 and add to (5)
7w-31s=0............(5)
35s-7w-28=0
--------------
4s-28=0
4s=28
4s/4=28/4
s=7
Put the value of s in (2)
m-5s=0............(2)
m-5(7)=0
m-35=0
m=35
Put the value of m in (1)
m-w-4=0...........(1)
35-w-4=0
-w+31=0
-w=-31
w=31
Present age of Man = m = 35 years old
Present age of Wife = w = 31 years old
Present age of Son = s = 7 years old

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Age_Word_Problems/517559: Please answer this..ASAP.Thanks..a man is four years older than his wife and 5 times as old as his son.when the so was born,the age of the wife is six-seventh that of her husband's age. Find the age of the wife..
1 solutions

Let wife’s age be W
Then man’s age = W + 4
S, or son’s age = 1%2F5 man’s age, or %281%2F5%29%28W+%2B+4%29, or %28W+%2B+4%29%2F5

W+-+S+=+%286%2F7%29%28W+%2B+4+-+S%29

W+-+%28W+%2B+4%29%2F5+=+%286%2F7%29+%2A+W+%2B+4+-+%28%28W+%2B+4%29%29%2F5

W+-+%28W+%2B+4%29%2F5+=+%286%2F7%29+%28%285W+%2B+20+-+W+-+4%29%2F5%29

35W – 7(W + 4) = 6(5W + 20 – W – 4) -------- Multiplying by LCD, 35

35W – 7W – 28 = 30W + 120 – 6W – 24

28W – 24W = 96 + 28

4W = 124

W, or wife’s age = 124%2F4, or highlight_green%2831%29

Send comments and “thank-yous” to “D” at MathMadEzy@aol.com