SOLUTION: if twice berthas age is increased by 4 less than 3 times her age the result is 71 equation 

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Question 517111: if twice berthas age is increased by 4 less than 3 times her age the result is 71 equation 
Answer by Maths68(1474) About Me  (Show Source):
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Let
Present age of Bertha = b

Twice Bertha's age = 2b
Three times of Bertha's age = 3b
if twice berthas age is increased by 4 less than 3 times her age the result is 71
(2b+4)-3b=71