SOLUTION: The ages of a mother and a daughter are 31 years and 7 years respectively. In how
many years will the mother’s age be 3/2 times that of daughter?
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many years will the mother’s age be 3/2 times that of daughter?
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Question 481392: The ages of a mother and a daughter are 31 years and 7 years respectively. In how
many years will the mother’s age be 3/2 times that of daughter? Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! Mother’s age=m=31
Daughter’s age=d=7
after y years mother and daughter will be
m+y= d+y
and the mother’s age be 3/2 times of daughter
(m+y)= (3/2) (d+y)
(m+y)= 3 (d+y)/2
2(m+y)=3(d+y)
2m+2y=3d+3y
2m-3d=3y-2y
y=2m-3d
y=2(31)-3(7)
y=62-21
y=41
In 41 years
