SOLUTION: A man is x years old while his son is y years old.the sum of their ages is twice the difference of their ages.if the product of their ages is 675,fine the age of the man
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Question 473344: A man is x years old while his son is y years old.the sum of their ages is twice the difference of their ages.if the product of their ages is 675,fine the age of the man Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A man is x years old while his son is y years old.
the sum of their ages is twice the difference of their ages.
x + y = 2(x-y)
x + y = 2x - 2y
x - 2x = -2y - y
-x = -3y
x = 3y
:
if the product of their ages is 675,
x * y = 675
replace x with (3y)
y(3y) = 675
3y^2 = 675
divide both sides by 3
y^2 =
y^2 = 225
y =
y = 15 yrs is the son's age
then
x = 3y
x = 3(15)
x = 45 is the man's age
:
:
Check solution by finding the product: 45 * 15 = 675
