SOLUTION: 10 years ago the father was 7times older than his son.2 years hence 2 times the fathers age will be 5 times the sons age.what are there present age.

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Question 391379: 10 years ago the father was 7times older than his son.2 years hence 2 times the fathers age will be 5 times the sons age.what are there present age.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

Let x and 7x represent the son's and father's ages 10 year ago.

Question states***

2(7x+12) = 5(x + 12)

solving for x

 14x + 24 = 5x = 60

      9x = 36

       x = 4, son's age 10 years ago. His father 28, ten year ago

 Son is NOW 14 and his father 38



CHECKING our Answer using status 2 years from NOW

 2*(38+2) = 5*(14+2) = 80