SOLUTION: Sharon's mom is eight more than twice her age. Her father is 3 years older than her mother. If the three family members have lived a total of 94 years, how old are each family memb
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Question 390084: Sharon's mom is eight more than twice her age. Her father is 3 years older than her mother. If the three family members have lived a total of 94 years, how old are each family member? Found 2 solutions by stanbon, mananth:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Sharon's mom is eight more than twice her age.
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m = 2s+8
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Her father is 3 years older than her mother.
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f = m+3
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If the three family members have lived a total of 94 years, how old are each family member?
s + m + f = 94
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Substitute for "s" and for "f" and solve for "m":
(m-8)/2 + m + m+3 = 94
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m-8 + 2m + 2m+6 = 188
5m = 190
m = 38 (mother's age)
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f = m+3 = 41 (father's age)
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s = (m-8)/2 = 15 (sharon's age)
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Cheers,
Stan H.
You can put this solution on YOUR website! Sharon's mom is eight more than twice her age. Her father is 3 years older than her mother. If the three family members have lived a total of 94 years, how old are each family member?
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Let Sharon's age be x
Mom = 2x+8
father = 2x+8+3= 2x+11
...
x+2x+8+2x+11=94
5x+19=94
-19 -19
5x=75
/5
x= 15 sharon's age.
Mother = 2x+8= 2*15+8=38 years
Father = 38+3 = 41 years
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