Question 384030: v
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! the present age of father is 4times of his son. 10 years before the age of father was 9times of his son age.find out their present age?
..
son= x years
father = 4x
..
10 years ago
son = x-10
father = 4x-10
...
4x-10=9(x-10)
4x-10=9x-90
4x-9x=-90+10
-5x=-80
/-5
x=16 son's age now
father's age = 4x = 4*16 = 64 years
...
m.ananth@hotmail.ca
|
|
|
