SOLUTION: A woman has a daughter and a son. The son is 3 years older than the daughter. In one year the woman will be six times as old as the daughter is now, and in 10 years, she will be 14

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Question 356881: A woman has a daughter and a son. The son is 3 years older than the daughter. In one year the woman will be six times as old as the daughter is now, and in 10 years, she will be 14 years older than the combined ages of her children. Whats the womans present age?
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
s=d+3 ----> d=s-3
w+1=6d ----> w=6d-1
w+10=s+d+3*14


w+10=s+d+42
6d-1+10=s+d+42
6(s-3)-1+10=s+s-3+42
6s-18+9=2s+39
6s-9=2s+39
6s-2s=9+39
4s=48
s=12
d=s-3=12-3=9
d=9
w=6d-1=6(9)-1=54-1=53

Woman 53 yrs old
Son 12 yrs old
Daughter 9 yrs old