SOLUTION: how do you solve: the sum of 4 times lisa's age and 7 times janes age is 169. jane is 1 year more than twice as old as lisa is. find each of their ages
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Question 354372: how do you solve: the sum of 4 times lisa's age and 7 times janes age is 169. jane is 1 year more than twice as old as lisa is. find each of their ages Answer by rfer(16322) (Show Source):
You can put this solution on YOUR website! 4x+7(2x+1)=169
4x+14x+7=169
18x=162
x=9
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4*9+7(2*9+1)=169
36+126+7=169
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L=x=9
A=2x+1=19
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