Question 347796: abe and his younger sister are 3 years apart in age. if the sum of their ages will be 35 next year, what are their ages now? Found 2 solutions by stanbon, MathTherapy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! abe and his younger sister are 3 years apart in age. if the sum of their ages will be 35 next year, what are their ages now?
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Equations:
a-s = 3
a+s = 35
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Add and solve for "a":
2a = 38
a = 19 (abe's age)
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Since a+s = 35, s = 35-19 = 16 (his sister's age)
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Cheers,
Stan H.
You can put this solution on YOUR website! abe and his younger sister are 3 years apart in age. if the sum of their ages will be 35 next year, what are their ages now?
Let Abe's current age be A, and his sister's age S
Then
A - S = 3_____eq (i)
(A + 1) + (S + 1) = 35____A + S = 33_____eq (ii)
A - S = 3______eq (i)
A + S = 33_____eq (ii)
2A = 36
A, or Abe's current age = , or years.
18 - S = 3____- S = - 15____S, or sister's current age = = years.
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