SOLUTION: Half of Henry's age added to 1/3 of Daisy's age is 11 years. Six years from now, the sum of their ages will be 40 years. How old is each?

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Question 339802: Half of Henry's age added to 1/3 of Daisy's age is 11 years.
Six years from now, the sum of their ages will be 40 years. How old is each?
Found 2 solutions by mananth, edjones:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let henry's age = x
Daisy's age be y
%28x%2F2%29+%2B%28y%2F3%29=+11%7D%7D%0D%0A%7B%7B%7B%283x%2B2y%29%2F6+=11
3x+2y=6*11
3x+2y=66.....................1
...
6 years from now
x+6+y+6 = 40 years
x+y+12=40
x+y=40-12
x+y= 28 .......................2
multiply equation 2 by -2 and add the equations
-2x-2y=-56
3x+2y=66
x=10 Henry's age
plug value of x in eauation 2
x+y =28
10+y=28
y=28-10
y=18 Daisy's age

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Let h=henry's age and d=daisy's
h/2 + d/3 = 11
3h+2d=66 multiply each side by 6.
.
h+6+d+6=40
h+d=28
h=28-d
.
3(28-d)+2d=66
84-3d+2d=66
-d=-18
d=18
h=10