SOLUTION: jan is twice as old as juwan, and rick is 5 years older than jan. if the sum of their ages is 35 years, find each of their ages

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: jan is twice as old as juwan, and rick is 5 years older than jan. if the sum of their ages is 35 years, find each of their ages      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 318909: jan is twice as old as juwan, and rick is 5 years older than jan. if the sum of their ages is 35 years, find each of their ages
Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
J-Jan's age
W-Juwan's age
R-Rick's age
.
.
.
J=2%2AW
R=5%2BJ
.
.
.
J%2BW%2BR=35
J%2BJ%2F2%2B5%2BJ=35
%285%2F2%29J=30
J=%282%2F5%29%2830%29
highlight%28+J=12%29
Then from above,
2%2AW=12
highlight%28W=6%29
.
.
.
+R=J%2B5=12%2B5
highlight%28R=17%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
jan is twice as old as juwan, and rick is 5 years older than jan. if the sum of their ages is 35 years, find each of their ages
--------------
Equations:
j = 2w
r = j+5
j+w+r = 35
--------------------
Substitute for "w" and for "r".
j + (j/2) + j+5 = 35
--------------------------------
Solve for "j":
(5/2)j = 30
(1/2)j = 6
j= 12 (Jan's age)
w= (1/2)j = 6 (juwan's age)
r = j+5 = 12+5 = 17 (rick's age)
=====================================
Cheers,
Stan H.
---