SOLUTION: A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence the father's present age is

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Question 314818: A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence the father's present age is
Found 2 solutions by mananth, karthiktcs:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Let son's age = x
father's age =3x
..
After 15 years
son's age = x+15
father's age = 3x+15
..
3x+15=2(x+15)
3x+15=2x+30
x=15.. son's age now
Father's age now = 3x = 45

Answer by karthiktcs(3) About Me  (Show Source):
You can put this solution on YOUR website!
let the present age of son be x
and the present age of father be 3x
after fifteen years
(3x+15)=2(x+15)
(3x+15)=(2x+30)
3x+15-2x-30=0
x-15=0
x=15
father age will be 3*15=45