SOLUTION: find three cosecutive intergers such that if twice the second is added to 7 times the first integer, the sum exceeds four times the last by 74

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Question 267240: find three cosecutive intergers such that if twice the second is added to 7 times the first integer, the sum exceeds four times the last by 74
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
not an age problem
x, x+1, x+2
x=first
x+1=second
x+2=third
2%28x%2B1%29%2B7x=4%28x%2B2%29%2B74
2x%2B2%2B7x=4x%2B8%2B74
2%2B9x=4x%2B82
5x=80
x=16
16,17,18