SOLUTION: Sue is 25 years older than Bill. in 4 years, Sue will be twice as old as Bill will be in 4 years. How old are they now? S=sue b=Bill s+25=b I am stuck after this. I don't

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Question 265601: Sue is 25 years older than Bill. in 4 years, Sue will be twice as old as Bill will be in 4 years. How old are they now?
S=sue
b=Bill
s+25=b
I am stuck after this. I don't understand how to come up with the second equation to solve.
Heather

Found 2 solutions by scott8148, Edwin McCravy:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
"Sue is 25 years older than Bill" ___ s = b + 25

"in 4 years, Sue will be twice as old as Bill will be in 4 years" ___ s + 4 = 2(b + 4)

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Sue is 25 years older than Bill. in 4 years, Sue will be twice as old as Bill will be in 4 years. How old are they now?
S=sue
b=Bill

s+25=b  (that's wrong!)

I am stuck after this. I don't understand how to come up with the second equation to solve.

Heather


Sue is 25 years older than Bill. 

Sue is the oldest so you have to add 25 to Bill's age to get Sue's age.
Not the other way around. So Sue's age = Bill's age + 25:

S+=+B%2B25

in 4 years, Sue will be twice as old as Bill will be in 4 years. How old are they now?

In 4 years, Sue will be S+4 and Bill will be B+4, and S+4 will be twice B+4, so

S%2B4=2%28B%2B4%29

So the system is
system%28S+=+B%2B25%2CS%2B4=2%28B%2B4%29%29

Can you solve that system. If not, post again asking how.

Solution: S=46, B=21

Sue is 46 and Bill is 21.

Sue is 46 which is 25 years older than Bill who is 21.  In 4 years,
Sue will be 50 and Bill will be 25 and she will be twice as old as 
Bill will be in 4 years.  So it checks.

Edwin