You can put this solution on YOUR website! A man 38 years old has a son 14 years old. How many years ago was the man seven times as old as his son? I also need the steps!
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let x = no. of years ago the man was 7 times the son
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Man's age x yrs ago = 7 time son's age x years ago; write an equation for this
38 - x = 7(14 - x)
38 - x = 98 - 7x
-x + 7x = 98 - 38
6x = 60
x =
x = 10 yrs ago, this was true
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Check it:
38 - 10 = 7(14 - 10)
28 = 7(4)
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