Question 255430: dave is three times older than Jim, and Jim is half Bill's age. If their average age is 64, what is Jim's age? Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! Let B = Bill, D = Dave, and J = JIm.
(i)
(ii) J = (1/2)B
(iii)
From (ii)
(iv) B = 2J.
Subbing (i), (ii) and (iv) into (iii), we get
(v)
(vi)
(vii)
This means that B = 64 and D = 96.
Jim = 32.
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