SOLUTION: A woman is 20 years more than the age of her daughter. In eleven years she will be 3 years less than twice her daughter's age, how old is each now?

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Question 242570: A woman is 20 years more than the age of her daughter. In eleven years she will be 3 years less than twice her daughter's age, how old is each now?

Found 2 solutions by College Student, stanbon:
Answer by College Student(505) (Show Source):
You can put this solution on YOUR website!
Let daughter = x
Let mom = x+20
.
In 11 years mom will be 3 years less than twice her daughter's age.
So, in 11 years mom will be (x+20)+11 and her daughter will be x+11, right?
Therefore, the equation would be:
Now solve for x to find the daughter's age, then add 20 to find mom's age.
.
I'll let you take it from here. :)

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A woman is 20 years more than the age of her daughter. In eleven years she will be 3 years less than twice her daughter's age, how old is each now?
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NOW DATA:
Let women's age be "w":
Let daughter's age be "d".
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Equations:
w = d + 20
w+11 = 2(d+11)-3
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Substitute for "w" and solve for "d":
d+20+11 = 2d + 22 -3
d+31 = 2d+19
d = 12 (age of the daughter Now)
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Since w = d + 20, w = 32 (the woman's age Now)
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Cheers,
Stan H.