SOLUTION: Mary is "y" years old. Her father is 4 times older than Mary. Her mother is 7 years younger than her father. If the three ages add up to 101 years, find the value of "y". Find the

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Question 22398: Mary is "y" years old. Her father is 4 times older than Mary. Her mother is 7 years younger than her father. If the three ages add up to 101 years, find the value of "y". Find the ages of Mary's parents.
Thanks in advance!
Found 2 solutions by elima, AnlytcPhil:
Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
Mary = y
Her father = 4y
Her mother = 4y-7
y+4y+4y-7=101
9y-7=101
9y=108
y=12
So Mary's age is 12, her father would be 4(12)=48,
Her maother would be 4(12)-7=48-7=41
Hope you understand
=)

Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
Mary is "y" years old. Her father is 4 times older than Mary. Her mother is 7

years younger than her father. If the three ages add up to 101 years, find the

value of "y". Find the ages of Mary's parents.



>>...Mary is "y" years old...<<



Translation:  Mary's age = y



>>...Her father is 4 times older than Mary...<<



Translation:  Father's age = 4y



>>...Her mother is 7 years younger than her father...<<



Transation:  Mother's age = 4y - 7



>>...the three ages add up to 101 years...<<<



Translation:  y + 4y + (4y - 7) = 101



Can you solve that for y?  If not post again



Answers: y = 12, Mary is 12, her father is 48 and her mother is 41.



Edwin

AnlytcPhil@aol.com