SOLUTION: A father is 32 years old and his daughter is 2 years old. He is now 16 times as old as his daughter. In how many years will he be only 4 times as old?

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Question 218793: A father is 32 years old and his daughter is 2 years old. He is now 16 times as old as his daughter. In how many years will he be only 4 times as old?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The big thing to notice here is that the difference
in their ages never changes
Let f = Father's age
Let d = Daughter's age
d+=+f+-+30 (always)
This is a ratio problem, so
f%2Fd+=+4%2F1 (4 times as old)
And, rewriting:
f%2F%28f-30%29+=+4%2F1
Multiply both sides by f-30
f+=+4%2A%28f-30%29
f+=+4f+-+120
3f+=+120
f+=+40
d+=+10
The Father will be 40 when he's 4 times as old as his Daughter
and that will be in 8 years since he's 32 now.
Notice that the fact that he was 16 times as old as his Daughter
when he was 32 was just thrown in to confuse you