Question 214369: Respected sir,
plz solve my maths problem.
1] In ten years ,david will be four times as old as aaron.twenty years ago,david was twice as old as ellen,if david is seven years older than ellen,how old is aaron?
waiting for yur reply.
thank u.
Found 2 solutions by Theo, drj: Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! let d = david's age now.
let a = aaron's age now.
let e = ellen's age now.
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In ten years ,david will be four times as old as aaron.
d+10 = 4*(a+10) = 4a+40
d = 4a+30
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Twenty years ago,david was twice as old as ellen.
d-20 = 2*(e-20)
d-20 = 2e-40
d = 2e-20
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If david is seven years older than ellen,how old is aaron?
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d = e+7
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Since d = 2e-20 and d = e+7, then 2e-20 must equal e+7
Equation to solve is:
2e-20 = e+7
This results in e = 27
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Ellen's age is 27
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Since d = e+7, this means that David is 7 years older than Ellen which makes David = 34 years old.
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Since d = 4a+30, and d = 34, then we have:
34 = 4a+30
This results in a = 1
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David is 34 years old
Aaron is 1 year old
Ellen is 27 years old.
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In 10 years Aaron is 11 and Dave is 44.
4 * 11 = 44 so this part of the original equation is good.
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20 years ago, David was twice as old as Ellen.
34-20 = 14
27-20 = 7
14/7 = 2 so this part of the equation is good also.
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Answer to your question is:
Aaron is 1 year old.
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Answer by drj(1380) (Show Source):
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