SOLUTION: Lee is 7 years older than phil. 11 years ago Lee was twice as old as phil was then. find their ages now

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Question 196107: Lee is 7 years older than phil. 11 years ago Lee was twice as old as phil was then. find their ages now
Found 3 solutions by stanbon, josmiceli, solver91311:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Lee is 7 years older than phil. 11 years ago Lee was twice as old as phil was then. find their ages now
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NOW DATA:
Let Phil be "x" yrs. old
Then Lee is "x+7" yrs. old
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11 years ago DATA:
Phil was "x-11" yrs. old
Lee was x+7-11 = "x-4" old
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Equation (based on 11 yrs. ago DATA:
x-4 = 2(x-11)
x-4 = 2x-22
x = 18 (Phil's age NOW)
x+7 = 25 (Lee's age NOW)
===============================
Cheers,
Stan H.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = Lee's age now
Then x+-+7= Phil's age now
x+-+11= Lee's age 11 years ago
x+-+7+-+11= Phil's age 11 years ago
x+-+11+=+2%2A%28x+-+7+-+11%29
x+-+11+=+2x+-+14+-+22
-11+=+x+-+36
36+-+11+=+x
x+=+25
x+-+7+=+18
Lee's age now is 25 and Phil's age now is 18
check answer:
x+-+11+=+2%2A%28x+-+7+-+11%29
25+-+11+=+2%2A%2818+-+11%29
14+=+2%2A7
14+=+14
OK

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let x represent Lee's age now. Then Phil is x - 7 now. Lee's age 11 years ago: x - 11 and Phil's age 11 years ago: x - 7 - 11 = x - 18, so:




Solve for x to get Lee's age.

John