SOLUTION: The sum of 4 times Lottie's age and 7 times Eddie's age is 169. Eddie is one year more than twice as old ad Lottie. Find each of their ages.
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Question 186499: The sum of 4 times Lottie's age and 7 times Eddie's age is 169. Eddie is one year more than twice as old ad Lottie. Find each of their ages. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Let L = Lottie's age now
Let E = Eddie's age now
:
Write an equation for each statement:
;
The sum of 4 times Lottie's age and 7 times Eddie's age is 169.
4L + 7E = 169
:
Eddie is one year more than twice as old ad Lottie.
E = 2L + 1
:
Find each of their ages.
:
Substitute (2L+1) for E in the 1st equation:
4L + 7(2L+1) = 169
:
4L + 14L + 7 = 169
:
18L = 169 - 7
L =
L = 9 yrs is Lottie's present age
then
E = 2(9) + 1
E = 19 yrs is Eddie's present age
;
;
Check solution in the statement,
"The sum of 4 times Lottie's age and 7 times Eddie's age is 169."
4(9) + 7(19) = 169, confirms our solution
