SOLUTION: Angel is twice as old as Gavin. In 3 years, Angel will be 13 years less than twice as old as Gavin. Find their ages now.

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Question 179723: Angel is twice as old as Gavin. In 3 years, Angel will be 13 years less than twice as old as Gavin. Find their ages now.
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Angel is twice as old as Gavin. In 3 years, Angel will be 13 years less than twice as old as Gavin. Find their ages now.
 
Angel's age now = A
Angel's age 3 years from now = A+3
Gavin's age now = G
Gavin's age 3 years from now = G+3

>>...Angel is twice as old as Gavin...<<

That says A = 2G

>>...In 3 years, Angel will be 13 years less than twice as old as Gavin...<<

That says:

(A+3) is 13 years less than twice (G+3)

or

A+3 = 2(G+3) - 13
A+3 = 2(G+3) - 13
A+3 = 2G+6-13
A+3 = 2G-7
  A = 2G-10



So we have the system:

system%28A=2G%2CA=2G-10%29

Substituting 2G for A in the second equation:

2G=2G-10

Subtract 2G from both sides

0=-10

So the system is inconsistent.  There is no solution.

Edwin