SOLUTION: Henry's age is 10 years less than four times Paul's age. The sum of their ages is 100. Find their ages.

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Question 175813: Henry's age is 10 years less than four times Paul's age. The sum of their ages is 100. Find their ages.
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

Paul's Age=x
Henry's Age=4x-10
Sum of both=100
Putting into eqn:
x%2B4x-10=100, working eqn
5x=100%2B10=110
cross%285%29x%2Fcross%285%29=cross%28110%2922%2Fcross%285%29
highlight%28x=22%29, Paul's Age
4%2A22-10=88-10=highlight%2878%29 Henry's Age
In doubt? Go back working eqn:
22%2B78=100
100=100
Thank you,
Jojo