SOLUTION: Henry's age is 10 years less than four times Paul's age. The sum of their ages is 100. Find their ages.

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Question 175295: Henry's age is 10 years less than four times Paul's age. The sum of their ages is 100. Find their ages.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Henry's age is 10 years less than four times Paul's age. The sum of their ages is 100. Find their ages.
:
let h = Henry's age
let p = Paul's age
:
Write an equation for each statement:
"Henry's age is 10 years less than four times Paul's age."
h = 4p - 10
:
"The sum of their ages is 100."
h + p = 100
:
Find their ages.
:
Substitute (4p-10) for h in the above equation
(4p-10) + p = 100
5p = 100 + 10
5p = 110
p = 110%2F5
p = 22 is Paul's age
:
I'll let you find Henry's age (h), substitute 22 for p, check your solutions in both equations