Question 170797: Paul is 12 and his father is 33. How many years ago was the father four times as old as the son? Found 2 solutions by Mathtut, stanbon:Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! if paul's age is p and fathers age is f
:f=33 and p=12 let x be the number of years ago the father was 4 times older than the son
:
f-x=4(p-x)
33-x=4(12-x)
:
33-x=48-4x
:
3x=15
: years ago father was 4 times older
You can put this solution on YOUR website! Paul is 12 and his father is 33. How many years ago was the father four times as old as the son?
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NOW DATA:
Paul = 12
Father = 33
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x years ago DATA:
Paul = 12-x
Father = 33-x
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EQUATION:
father = 4*paul
33-x = 4(12-x)
33-x = 48 - 4x
3x = 15
x = 5 (# of years ago)
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Cheers,
Stan H.
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