SOLUTION: tumi is selling two types of umbrellas.he sells type c at R45 a pair he sells type d at R30 .if he sold 16 pairs in total and had a totl income of R585,how many pairs of sock c did
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Question 1207199: tumi is selling two types of umbrellas.he sells type c at R45 a pair he sells type d at R30 .if he sold 16 pairs in total and had a totl income of R585,how many pairs of sock c did h did Sal sell?
I can't imagine how you would be so careless as to post a question the way you did....
But the meaning is clear: there are two types of items, costing R45 and R30 each; and there are a total of 16 items with a total cost of R585.
The setup for a formal algebraic solution would look something like this:
c = # of items of type
d = # of items of type d
c+d = 16 [the total number of items is 16]
45c+30d = 585 [the total cost is 585]
Multiply the first equation by 30...
30c+30d = 480
... and find the difference between that result and the second equation:
15c = 105
c = 7
ANSWER: c = 7 of type c and 16-7 = 9 of type d
CHECK: 7(45)+9(30) = 315+270 = 585
A quick, informal mental solution -- using exactly the same calculations -- can be obtained using logical reasoning:
If all 16 items were type c, the total cost would be 16(30) = 480
The actual total cost is 585, which is 105 higher
The difference in cost between type c and type d is 15
The number of items of the higher-priced type is 105/15 = 7.
You can put this solution on YOUR website! .
tumi is selling two types of umbrellas.he sells type c at R45 a pair he sells type d at R30 .
if he sold 16 pairs in total and had a totl income of R585,how many pairs of sock c did h did Sal sell?
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Solve using one unknown and one equation.
Let x be the number of items of type "c".
Then the number of items of type "d" is 16-x.
Write the total money equation
45x + 30*(16-x) = 585 dollars (revenue).
Divide both sides by 15
3x + 2(16-x) = 39.
Simplify and find x
3x + 32 - 2x = 39
3x - 2x = 39 - 32
x = 7.
ANSWER. 7 items of type "c".
