SOLUTION: Twelve years ago, the age of the father was three times the age of his daughter. After twelve years, father’s age will be twice than of his daughter. The ratio present ages is?

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Question 1202393: Twelve years ago, the age of the father was three times the age of his daughter. After twelve years, father’s age will be twice than of his daughter. The ratio present ages is?
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

Twelve years ago, the age of the father was three times the age of his daughter.
12 years ago daughter's age be x years
father's age = 3x
After twelve years, father’s age will be twice than of his daughter. The ratio present ages is?
after(12+12)= 24 years
3x+24= 2(x+24)
3x+24= 2x+48
3x-2x= 48-24
x =24
Present age of daughter = 24+12 =36 years.
Father;s age = 72+12 = 84
Ratio = 36/84 = 3/7




Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
y-12=3%28x-12%29
y-12=3x-36
-
y%2B12=2%28x%2B12%29
y%2B12=2x%2B24
-

system%28y-3x=-24%2Cy-2x=12%29

system%283x-y=24%2C2x-y=-12%29

x=36

y=3x-24
y=3%2A36-24
y=84

Ratio of present ages? Father to Daughter: 84%2F36=42%2F18=highlight%287%2F3%29