Question 1201109: The sum of the ages of ral and shein is 28. Ten years from now, ral age will be twice shein age. Find their age now
Found 4 solutions by mananth, greenestamps, josgarithmetic, ikleyn:
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! the sum of ages of Ral and shein is 28 years
If rals age is x years
Shein's age will be 28-x
Ten years later
Ral's age willbe x+10 years
Shein's age will be (28-x)+10 years= 38-x
ral age will be twice shein age.
x+10 = 2(38-x)
x+10 = 76-2x
3x=66
x=22 Ral's age
Shein's age = 28-22=6 years
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
Starting with the information that Ral will be twice as old as Shein in 10 years....
x = Shein's age 10 years from now
2x = Ral's age 10 years from now
Their ages now are then
Shein: x-10
Ral: 2x-10
The sum of their current ages is 28:
(x-10)+(2x-10) = 28
3x-20 = 28
3x = 48
x = 48/3 = 16
ANSWERS:
Shein's current age: x-10 = 16-10 = 6
Ral's current age: 2x-10 = 32-10 = 22
Answer by josgarithmetic(39620)  (Show Source):
Answer by ikleyn(52803)  (Show Source):
You can put this solution on YOUR website! .
This problem is good for mental solution in couple of lines.
Indeed, in 10 years from now, Ral will be twice Shein's age, and the sum of their ages will be 28+10+10 = 48.
If one of the numbers is twice the other number and their sum is 48, then the numbers are 16 and 32:
+------------------------------------------------------------------------+
| it is how a human brain should react automatically on such information |
+------------------------------------------------------------------------+
Hence, the Ral age is 16-10 = 6 years now,
while the Shein age is 32-10 = 22 years now.
Solved.
|
|
|
