SOLUTION: The width of a photo is 5 inches more than its length. A border of two inches is placed all around the photo. The area covered by the photo and its border is 104 square inches.

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Question 1185651: The width of a photo is 5 inches more than its length. A border of two inches
is placed all around the photo. The area covered by the photo and its border
is 104 square inches. Find the dimensions of the photo itself.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Length of photo, L
Width of photo, L+5

Border around photo is 2 inches.
Whole piece length, L%2B2%2A2=L%2B4
Whole piece width, L%2B5%2B2%2A2=L%2B9

AREA of photo and border, %28L%2B4%29%28L%2B9%29=104 in square inches.
Solve for L using quadratic equation with factoring or general solution if you want to, or look at----------


See the factors of 104 maybe differ by 5;
104=4%2A26=8%2A13;
system%28L%2B4=8%2C+and%2C+L%2B9=13%29
highlight%28L=4%29

Photograph itself is 4 inches by 9 inches.