Question 1183266: a man is six years older than his wife.six years ago the ratio of their ages wa 7:6 find their present ages
Found 3 solutions by MathLover1, MathTherapy, greenestamps:
Answer by MathLover1(20850)   (Show Source):
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
a man is six years older than his wife.six years ago the ratio of their ages wa 7:6 find their present ages
If you want to torture yourself, you can follow that woman's formation of this problem.
Correct way to do this is:
Let the wife's age be W
Then man's is W + 6
Now, since the man's older, it's obvious that his age would represent the larger part of the ratio, hence, 7 for him.
We then get: 
6W = 7(W - 6) ------ Cross-multiplying
6W = 7W - 42
6W - 7W = - 42
- W = - 42
Wife's age, or 
Do you think you can find the man's age?
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
Given that the ratio of their ages 6 years ago was 7:6, I would solve the problem like this:
Let their ages 6 years ago be 7x and 6x. (That is a very common way to start on a problem like this where a ratio is given.)
The difference between their ages 6 years ago was 7x-6x=x.
But the difference between their ages is 6 years. So x=6, and their ages 6 years ago were 7x=42 and 6x=36.
So now, 6 years later, their ages are 42+6=48 and 36+6=42.
ANSWERS: The man is now 48; his wife is 42.
|
|
|
