SOLUTION: The sum of the ages of Dylan and Noelle is 80 years. 10 years ago, Dylan's age was 3 times Noelle's age. How old is Dylan now?

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Question 1177439: The sum of the ages of Dylan and Noelle is 80 years. 10 years ago, Dylan's age was 3 times Noelle's age. How old is Dylan now?
Found 4 solutions by Boreal, mananth, greenestamps, josgarithmetic:
Answer by Boreal(15235)   (Show Source):
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D+N=80
(D-10)=3(N-10)
D-10=3N-30
D=3N-20
so 4N-20=80
N=25
D=55
10 years ago it was 15 and 45 for N and D respectively.
Dylan is 55 now.

Answer by mananth(16946)   (Show Source):
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The sum of the ages of Dylan and Noelle is 80 years.
D+N =80
multiply by 3
3D +3N =240----------------(1)
10 years ago, Dylan's age was 3 times Noelle's age.?
D-10= 3(N-10)
D-10 =3N -30
D-3N =-20 --------------(2)
Add 1 and 2
4d =220
D= 55
dylan is 55 years now

Answer by greenestamps(13200)   (Show Source):
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There are an endless number of different ways to set up this problem for solving. With some experience, you can learn how to set up problems to make the work of solving them as easy as possible.

Given that Dylan 10 years ago was 3 times as old as Nicole, I would set up the problem like this:

Let x = Nicole's age 10 years ago
Then 3x = Dylan's age 10 years ago

The sum of their current ages is 80, so 10 years ago that sum was 60.

Dylan's age 10 years ago was 3x=45, so his age now is 55.

Answer by josgarithmetic(39620)   (Show Source):
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for ages d Dylan and n Noelle, the description very literally is:

Question just asks for d.
Starting approaches to solve can vary.