SOLUTION: Nate is 5 years older than 4 times Josh’s age. If their ages add together to a total of 100, how old is each?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Nate is 5 years older than 4 times Josh’s age. If their ages add together to a total of 100, how old is each?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1175199: Nate is 5 years older than 4 times Josh’s age. If their ages add together to a total of 100, how old is each?

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let Nate's age be N and Josh's age J
if Nate is 5+years older than 4 times Josh’s age, we have
N=4J%2B5.....eq.1
if their ages add together to a total of 100, we have
N%2BJ=100 .....eq.2....substitute N from eq.1
4J%2B5%2BJ=100.....solve for J
5J=100-5
5J=95
J=95%2F5
J=19

go to
N=4J%2B5.....eq.1, substitute J
N=4%2A19%2B5
N=81

how old is each?
answer: Nate is 81+ years old and Josh is 19+ years old