SOLUTION: Chad's mom is ten years younger than three times Chad's age. His grandpa is 28 years older than his mom. If Chad's grandpa were three years older, he would be four times Chad's age

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Question 1170721: Chad's mom is ten years younger than three times Chad's age. His grandpa is 28 years older than his mom. If Chad's grandpa were three years older, he would be four times Chad's age. Find the age of his grandpa.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
m = Mom's present age
c = Chad's
g = Grandpa's
:
Write an equation for each statement, arrange to get c an g in terms of m
:
Chad's mom is ten years younger than three times Chad's age.
m + 10 = 3c
3c = m + 10
c = %28m%2B10%29%2F3
His grandpa is 28 years older than his mom.
g = m + 28
If Chad's grandpa were three years older, he would be four times Chad's age.
g + 3 = 4c
Replace c with %28m%2B10%29%2F3 and g with (m+28)
(m+28) + 3 = 4(%28m%2B10%29%2F3)
m + 31 = 4(%28m%2B10%29%2F3)
Multiply both sides by 3, get rid of the fraction on the right
3(m+31) = 4(m+10)
3m + 93 = 4m + 40
93 - 40 = 4m - 3m
53 = m
Mom's age is 53
Find the age of his grandpa.
g = 53 + 28
g = 81 is grandpa's age
:
:
Check solution in the statement
"If Chad's grandpa were three years older, he would be four times Chad's age."
(Chad is %2853%2B10%29%2F3 = 21)
81 + 3 = 4(21)
84 = 84