SOLUTION: The difference of three times Faye’s age and four times Joshua’s age is 31. If Faye’s age is five more than twice Joshua’s age, how old is Faye?

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Question 1169526: The difference of three times Faye’s age and four times Joshua’s age is 31. If Faye’s age is five more than twice Joshua’s age, how old is Faye?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
f Faye
j Joshua
system%283f-4j=31%2Cf=5%2B5j%29
.
.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The difference of three times Faye’s age and four times Joshua’s age is 31. If Faye’s age is five more than twice Joshua’s age, how old is Faye?
Let Faye's, and Joshua's ages be F and J, respectively

Then we get: 3F + 4J = 31 ------ eq (i)

Also, F = 2J + 5____F - 2J = 5 ------ eq (ii)

Multiply eq (ii) by 2 to get eq (iii), and then add eqs (iii) and (i).

This will ELIMINATE J, or Joshua's age and give you Faye's!