SOLUTION: The sum of the present ages of Eric and his father is 58 years. In 10 years, his father will be twice as old as Eric will be at that time. Find their present ages.
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Question 1166313: The sum of the present ages of Eric and his father is 58 years. In 10 years, his father will be twice as old as Eric will be at that time. Find their present ages. Answer by ikleyn(52788) (Show Source):
E + F = 58 (1) (the sum of current ages)
F + 10 = 2*(E + 10) (2) (in 10 years)
From equation (1), express F = 58 - E and substitute it into equation (2), replacing F there.
(58 - E) + 10 = 2E + 20
58 + 10 - 20 = 2E + e
48 = 3E
E = 48/3 = 16.
ANSWER. Eric is 16 years old. The father is 58-16 = 42 years old.
