Question 1157661: Sally has two more jelly beans than joe. Sally's jelly beans + Joe's jelly beans equals 78. How many jelly beans does each have? Found 3 solutions by josgarithmetic, ikleyn, Alan3354:Answer by josgarithmetic(39618) (Show Source):
Joe + Sally = = 78.
It is the same as to say
Joe + (Joe + 2) = 78.
It is the same as
2*Joe = 78 - 2
2*Joe = 76
Joe = 76/2 = 38.
Answer. Joe has 38 jelly beans. Sally gas 2 more, i.e. 38+2 = 40 jelly beans.
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Dear tutors, as you read the problem, you should understand from the tone, in which it is written,
that the problem is designed and intended for very young students (4-5 grades), who DEFINITELY don't know
and do not understand what is the system of algebraic equation. Therefore, the solution for them should be appropriate !
You can put this solution on YOUR website! Sally has two more jelly beans than joe. Sally's jelly beans + Joe's jelly beans equals 78. How many jelly beans does each have?
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S + J = 78
S - J = 2
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