SOLUTION: A man is 3 years less than five times his son's age. The sum of their age is 37 years. Determine the father's age.

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Question 1155066: A man is 3 years less than five times his son's age. The sum of their age is 37 years. Determine the father's age.
Found 2 solutions by josmiceli, ikleyn:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = the son's age
+5x+-+3+ = the father's age
-----------------------------------
+x+%2B+5x+-+3+=+37+
+6x+=+40+
+x+=+20%2F3+
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The father's age is:
+5x+-+3+=+5%2A%2820%2F3%29+-+3+
+5x+-+3+=+100%2F3+-+9%2F3+
+5x+-+3+=+91%2F3+
+5x+-+3+=+30+%2B+1%2F3+
and
+%281%2F3%29%2A12+=+4+ months
The father is 30 years and 4 months
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check the answer:
+x+%2B+5x+-+3+=+37+
+20%2F3+%2B+5%2A%28+20%2F3+%29+-+3+=+37+
Multiply both sides by +3+
+20+%2B+100+-+9+=+111+
+111+=+111+
OK
check the math

Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
.

As it is worded,  printed,  posted and presented,  the problem  HAS  NO  SOLUTION  in integer numbers.

Therefore,  the problem is  DEFECTIVE.