Question 1151139: Dyke is 27 years old than his daughter. In 10 years he will be twice as old as his daughter. How old they are now?
Please help me. Found 2 solutions by ikleyn, greenestamps:Answer by ikleyn(52802) (Show Source):
You can put this solution on YOUR website! .
Dyke is 27 years older than his daughter.
In 10 years he will be twice as old as his daughter. How old they are now?
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Let x be the daughter's age.
Then his father's age is (x+27) years.
In 10 years,
the daughter's age will be (x+10) years, while
the father's age will be (x+27+10) = (x+37) years.
You are given
x+37 = 2*(x+10).
It is your basic equation.
As soon as you got it, you just solved the problem in half.
To solve it COMPLETELY, simplify your equation step by step
x + 37 = 2x + 20
37 - 20 = 2x - x
17 = x.
ANSWER. The daughter is 17 years old. The father is 27 years older, i.e. 17+27 = 44 years old.
Solved.
Now YOU check it ON YOUR OWN that all conditions of the problem are satisfied.
