SOLUTION: today the father is 51 years and his son is 9 years . In how many years the father will be four times as old as his son?
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Question 1150570
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today the father is 51 years and his son is 9 years . In how many years the father will be four times as old as his son?
Found 2 solutions by
ikleyn, greenestamps
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Answer by
ikleyn(52788)
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51 + x = 4*(x+9) 51 + x = 4x + 36 51 - 36 = 4x - x 15 = 3x x = 15/3 = 5.
ANSWER
. In 5 years.
Answer by
greenestamps(13200)
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The difference in their ages is 51-9 = 42 years.
When the father is 4 times as old as his son, their ages will be 4x and x; the difference will be 3x.
3x = 42
x = 42/3 = 14
The father will be 4 times as old as his son when the son is x=14 and the father is 4x=56.
Since the father is now 51, that will be 5 years from now.