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Jane is 4 years
older
than Paul.
The sum of three times janes age and two times Paul’s age is 67. How old are Jane and Paul?
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Let x be the Jane age; then the Paul's age is (x-4) years.
From the condition, you have this equation
3x + 2*(x-4) = 67.
Solve it for x, the Jane's age.
Then evaluate (x-4), the Paul's age.