Question 1144195: David is two years older than peter and five years older than John.Their ages add up to 44. How old is John?
Found 3 solutions by Theo, ikleyn, MathTherapy:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! let d = david's age.
let p = peter's age.
let j = john's age.
david is 2 years older than peter, therefore d = p + 2.
david is 5 years older than john, therefore d = j + 5.
you are given that d + p + j = 44
in d = p + 2, solve for p to get:
p = d - 2.
in d = j + 5, solve for j to get:
j = d - 5.
replace p and j with their equivalent values in d to get:
d + p + j = 44 becomes:
d + (d - 2) + (d - 5) = 44
combine like terms to get:
3 * d - 7 = 44
add 7 to both sides of the equation to get 3 * d = 51
solve for d to get d = 51 / 3 = 17.
since d = p + 2, then p = 15.
since d = j + 5, then j = 12.
d + p + j becomes 17 + 15 + 12 = 44
the values for d and p and j are confirmed to be good.
the solution is that john is 12 years old.
Answer by ikleyn(52788)  (Show Source):
You can put this solution on YOUR website! .
Let x be the David's age.
Then Peter is (x-2) years old, while John is (x-5) years old.
The total of their ages is 44, which gives you an equation
x + (x-2) + (x-5) = 44,
Or
3x - 7 = 44,
3x = 44 + 7 = 51,
x = 51/3 = 17.
ANSWER. John's age is x-5 = 17-5 = 12 years.
This problem deserves to be solved in short, simple and clear form.
As any other problem, too . . .
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! David is two years older than peter and five years older than John.Their ages add up to 44. How old is John?
Let John's age be J
Then David's is: J + 5, and Paul's is: J + 5 - 2, or J + 3
With ages totaling 44 years, we get: J + J + 5 + J + 3 = 44
3J = 36
J, or 
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