SOLUTION: A woman is 44 years old now. In 12 years time she will be twice as old as her daughter. Write down the statements in algebraic form.Hence determine the age of the daughter now.

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Question 1141204: A woman is 44 years old now. In 12 years time she will be twice as old as her daughter. Write down the statements in algebraic form.Hence determine the age of the daughter now.
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+44+ = woman's age now
Let +x+ = her daughter's age now
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+44+%2B+12+=+2%2A%28+x+%2B+12+%29+
+56+=+2x+%2B+24+
+2x+=+32+
+x+=+16+
The daughter is 16 now
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check:
+44+%2B+12+=+2%2A%28+16+%2B+12+%29+
+56+=+2%2A28+
+56+=+56+
OK

Answer by MathTherapy(10553) About Me  (Show Source):
You can put this solution on YOUR website!
A woman is 44 years old now. In 12 years time she will be twice as old as her daughter. Write down the statements in algebraic form.Hence determine the age of the daughter now.
Woman is 44, and in 12 years, she'll be 44 + 12, or 56. Her daughter then, would be 1%2F2 her age, or 28 years-old.
Therefore,