SOLUTION: The sum of two numbers is 20. Twice the first number plus four times the second is 64. Find the numbers

The two equations for the given conditions are:

 n +  m = 20    (1)

2n + 4m = 64    (2)



(2) -->  n + 2m = 32



Subtract (1) from this to get m:

  n + 2m  = 32

- n  - m  = -20

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  (you do the rest here)



 then plug in that value into (1) or (2) and solve for n.  





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