SOLUTION: Mother is four times old as Mary. Five years ago, she was seven times as old. How old will each be in five years?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Mother is four times old as Mary. Five years ago, she was seven times as old. How old will each be in five years?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1134466: Mother is four times old as Mary. Five years ago, she was seven times as old. How old will each be in five years?
Answer by mathsolverplus(88) About Me  (Show Source):
You can put this solution on YOUR website!
Mother's age = x
Mary's age = y
Present: x = 4y Mother is four times old as Mary
Past: x-5 = 7(y-5) Both age needs to be subtracted from five first.
4y-5=7y-35
-3y=-30
y=10
x=40 and y=10
Mother's age in five years = 40+5 =45 years old
Mary's age in five years = 10+5 = 15 years old

For more additional instant FREE math help, please check out and follow us on social media!!
Instagram (@mathsolver.plus) : https://www.instagram.com/mathsolver.plus/
Twitter (@MathSolverPlus): https://twitter.com/MathSolverPlus
Snapchat (@mathsolverplus)
Email: mathsolverplus@gmail.com