SOLUTION: A teacher has two students, one two times as old as the other. The teacher is five times as old as the older student, and in 5 years she will be five times as old as her younger st
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Question 1133073: A teacher has two students, one two times as old as the other. The teacher is five times as old as the older student, and in 5 years she will be five times as old as her younger student. Find the teacher’s present age.
PLS HELP! Found 2 solutions by math_helper, ikleyn:Answer by math_helper(2461) (Show Source):
You can put this solution on YOUR website! Let x= Age of younger student
Then
2x is the age of the older student
5(2x)=10x is the age of the teacher
10x+5 = 5(x+5)
Solve the above for x to get x=4 —> teacher is 10x=40 years old
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Ans: the teacher is 40 years old
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Check:
Younger student is 4
Older student is 2*4=8
Teacher is 40 (=5*8, in agreement with teacher being 5 times as old as older student)
In 5 years,
Younger student will be 9
Teacher will be 45 (= 9*5, so this answer checks)
From the condition, the students ages are x and 2x, while the teacher age is 5*(2x) = 10x years.
The condition also says that
10x + 5 = 5*(x+5) ("in 5 years she (= the teacher) will be five times as old as her younger student".)
Solve this equation and complete the solution on your own.
ANSWER. The teacher is 40 years old.
