SOLUTION: Four years ago, Richard is three times the age of his son André. In 10 years, he will be twice André’s age. How old are they now?

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Question 1133056: Four years ago, Richard is three times the age of his son André. In 10 years, he will be twice André’s age. How old are they now?

Found 2 solutions by MathLover1, josmiceli:
Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website!

let’s Richard’s age be and André’s age be
Four years ago, Richard was years old and André years old
Richard is three times the age of his son André:

..........eq.1

In years, Richard will be years old and André years old
and Richard will be twice André’s age

.........eq.2

from eq.1 and eq.2 we have

go back to eq.1

..........eq.1 substitute for

Richard’s is and André’s is old now

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Let = Richard's age now
Let = Andre's age now
---------------------------------------
(1)
(2)
-------------------------------------
(2)
(2)
and
(1)
(1)
Subtract (1) from (2)
(2)
(1)
----------------------------

and
(2)
(2)
(2)
-----------------------------
Richard is 46
Andre is 18
--------------------
check:
(1)
(1)
(1)
(1)
OK
(2)
(2)
(2)
(2)
OK