SOLUTION: Jessa is 15 years older than her student.In 15 years, twice her age will be thrice the age of her student.Find the present age of her student.
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Question 1132480: Jessa is 15 years older than her student.In 15 years, twice her age will be thrice the age of her student.Find the present age of her student. Found 2 solutions by ikleyn, greenestamps:Answer by ikleyn(52798) (Show Source):
Let x be the present age of her student.
Then Jessa's present age is (x+15) years.
In 15 years . . .
2*((x+15) + 15) = 3*(x+15).
It is your basic equation. Simplify and solve it step by step
2x + 60 = 3x + 45
60 - 45 = 3x - 2x ====> x = 15. <<<---=== the student's present age. ANSWERCHECK. Then Jessa's present age is 15 + 15 = 30 years. ("Jessa is 15 years older than her student.")
In 15 years: Jessa is 45 years old; the student is 15 + 15 = 30 years old.
2*45 = 90 = 3*30. ! Precisely correct !
